Mathématiques

Question

Bjr je suis bloquer a cette exercice merci .
Exercice 1 : Simplifier les expressions suivantes.

A= 11 - (7 - b ) + (4 + a ) + 6 + ( b - 3 )
B= 15 - (10-(6-b)+(5+4a)
C= -(c + 7) + (8 - b)
D= (3 - b) + (b + 8)

2 Réponse

  • Bonjour,

    A= 11 - (7 - b ) + (4 + a ) + 6 + ( b - 3 )
    A = 11 - 7 + b + 4 + a + 6 + b - 3
    A = a + b + b + 11 + 4 + 6 - 7 - 3
    A = a + 2b + 21 - 10
    A = a + 2b + 11

    B= 15 - (10-(6-b)+(5+4a)
    B = 15 - (10 - 6 + b ) + 5 + 4a
    B = 15 - 10 + 6 - b + 5 + 4a
    B = 4a - b + 15 - 10 + 6 + 5
    B = 4a - b - 10 + 26
    B = 4a - b + 16

    C= -(c + 7) + (8 - b)
    C = - c - 7 + 8 - b
    C = - b - c + 1

    D= (3 - b) + (b + 8)
    D = 3 - b + b + 8
    D = 11
  • Bonjour

    A = 11 - (7 - b ) + (4 + a ) + 6 + ( b - 3 )
    A = 11 - 7 + b + 4 + a + 6 + b - 3
    A = a + b + b + 11 + 4 - 7 - 3
    A = a + 2b + 11

    B = 15 - (10-(6-b)+(5+4a)
    B = 15 - ( 10 - 6 + b) + 5 + 4a
    B = 15 - 10 + 6 - b + 5 + 4a
    B = 4a - b + 16

    C = - (c + 7) + (8 - b)
    C = - c - 7 + 8 - b
    C = - b - c + 1

    D = (3 - b) + (b + 8)
    D = 3 - b + b + 8
    D = 11

    Voilà ^^

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