Mathématiques

Question

Si quelqu’un pouvais m’aider.. svp
Si quelqu’un pouvais m’aider.. svp

1 Réponse

  • cos(2001π/4)=cos(π/4)=√2/2
    sin(2001π/4)=sin(π/4)=√2/2

    cos(199π/6)=cos(-π/6)=√3/2
    sin(199π/4)=sin(-π/6)=-1/2

    cos(-77π/3)=cos(π/3)=1/2
    sin(-77π/3)=sin(π/3)=√3/2

    cos(-41π/2)=cos(-π/2)=0
    sin(-41π/2)=sin(-π/2)=-1

    cos(106π)=cos(0)=1
    sin(106π)=sin(0)=0