Mathématiques

Question

Développer puis réduire
A= (x - 4 )(x + 6)
B=2(x-1)+2(y+2)-2(1+z)
C=xy+ yz +xz - y (x-1)-z(y-1)-x(z-1)
D=x-((1-y)-(z+1))

2 Réponse

  • A= x*x+x*6-4*x-4*6 = x²+6x-4x-24= x²+2x-24

    B= 2x-2+2y+4-2-2z = 2x+2y-2z 

    C= xy+yz+xz-yx+y -zy+z-xz+x =x+y+z

    D= x-(1-y-z-1)=x+y+z 

  • Bonjour

    A= (x-4)(x+6)
    A = x² + 6x - 4x - 24
    A = x² + 2x - 24

    B = 2(x-1) + 2(y+2) - 2(1+z)
    B = 2x - 2 + 2y + 4 - 2 - 2z
    B = 2x + 2y -2z

    C = xy+ yz +xz - y(x-1) - z(y-1) - x(z-1)
    C = xy + yz +xz - yx + y - zy + z -xz + x
    C = x + y + z

    D = x - ((1-y) - (z+1))
    D = x - (1 - y - z - 1)
    D = x + y + z

    Voilà ^^

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