Bonjour qui peux m'aider svp ? B=(2x-3)²-(2x-3)(x+1) 1/ develloper B 2/ Calculez B pour x= 4 Voila merci

1. B = (2x-3)²-(2x-3)(x+1) 
B = 4x²-12x+9-(2x²+2x-3x-3)
B = 4x²-12x+9-2x²-2x+3x+3
B = 2x²-11x+12

2. 2*4²-11*4+12 
= 2*16-44+12
= 32-44+12
= 0

B=(2x-3)²-(2x-3)(x+1)

1/ B= (2x - 3) (2x-3 ) - (2x - 3) (x+1) = (2x-3) ( 2x-3 - 1* (x+1)) = (2x-3) (x-4) = 2x^2 -8x-3x+12 = 2x^2- 11x + 12
2/ Calculez B pour x= 4

B= 2* 16 - 44 + 12 = 0