B=(2x-1)(2x-1)+(2x-1)(3x+5) D= (2x+7)(5x+4)-(2x+7)(x+11) devellopper et reduire B devellopper et reduire D fa
Question
B=(2x-1)(2x-1)+(2x-1)(3x+5) D= (2x+7)(5x+4)-(2x+7)(x+11)
devellopper et reduire B devellopper et reduire D
factoriserB factoriser D
C=(x-1)(2x+5)-(x+1)(2x+5)
*devellopper et reduire C
factoriser C
A= (x+2)(x-3)+(x-3)
develloper et reduire A
factoriser A.
puis calculer A pour x=3
2 Réponse
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1. Réponse isapaul
factoriser
A = (x+2)(x-3)+(x-3) = (x-3) [(x+2)+1] = (x-3)(x+3) = x²-9
B = (2x-1)(2x-1)+(2x-1)(3x+5) = (2x-1)[(2x-1)+(3x+5)]= (2x-1)(5x+4)
C= (x-1)(2x+5)-(x-1)(2x+5) = (2x+5)[(x-1)-(x-1)]=(2x+5)-2 = -2(2x+5)
D = (2x+7)(5x+4)-(2x+7)(x+11) = (2x+7)[(5x+4)-(x+11)]=(2x+7)(4x-7)
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2. Réponse StacyMsl
A = (x+2)(x-3)+(x-3)
= (x-3) [(x+2)+1]
= (x-3)(x+3) = x²-9
B = (2x-1)(2x-1)+(2x-1)(3x+5)
= (2x-1)[(2x-1)+(3x+5)]
= (2x-1)(5x+4)