bns aide moi svp 1-soient A(22π/3) ; B(-35π/6) ; C(39π/4) trois pts sur un cercle trigonométrique calculer les mesures et les mesures principales des angles ori

22π/3 = 18π/3 + 4π/3 = 4π/3 = 240°

-35π/6 = -36π/6 + π/6 = π/6 = 30°

39π/4 = 32π/4 + 7π/4 = 7π/4 = 315°

angles (OA;OB) = (360° - 240°) + 30° = 150° = 5π/6
            (OB;OC) = 315° - 30° = 285 ° = 19π/12
            (OC;OA) = (360° - 315°) + 240° = 285° = 19π/12 aussi !